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\title {Logic I \\ Lecture 07}
 
\maketitle
 

Logic I

Lecture 07

\def \ititle {Logic I}
\def \isubtitle {Lecture 07}
\begin{center}
{\Large
\textbf{\ititle}: \isubtitle
}
 
\iemail %
\end{center}
Readings refer to sections of the course textbook, \emph{Language, Proof and Logic}.
 
\section{Recap: Structural Ambiguity in Natural Languages}
 

The Syntax of awFOL

 
\section{The Syntax of awFOL}
\emph{Reading:} §9.3
 
\section{The Syntax of awFOL}

What do the brackets mean?

We define what counts as a sentence of awFOL using rules. E.g.:
1. If * and \# are sentences, then so is(* ∧ \#)
2. If * and \# are sentences, then so is (* ∨ \#)
3. P, Q, R, … are sentences
4. If * is a sentence, then ¬* is a sentence
So:
a. P is a sentence // rule 3
b. ¬P is a sentence // rule 4, a
c. ( ¬P ∧ Q ) is a sentence // rule 1, b, a
There is no structural ambiguity in awFOL because these rules are formulated to ensure that for any awFOL sentence, there is exactly one way of constructing it.
 

¬P ∨ ¬Q compared with ¬(P ∨ Q)

 
\section{¬P ∨ ¬Q compared with ¬(P ∨ Q)}
\emph{Reading:} §3.5
 
\section{¬P ∨ ¬Q compared with ¬(P ∨ Q)}
 

Logically Entails

 
\section{Logically Entails}
 
\section{Logically Entails}

‘there are some truth tables questions in which you ask whether one sentence logically entails another, and [we] don't know what “logically entails” means.’

One sentence logically entails another just if there’s no possible situation where the first is true and the second false.
I ask you about logical conseuqence in many of the truth table exercises.
Consider the example we were just looking at.
¬P ∨ ¬Q does not logically entail ¬(P ∨ Q). How do I know? Because here we have a possible situation (P:F, Q:T) in which ¬P ∨ ¬Q is true and ¬(P ∨ Q) is false
What about the converse? Does ¬(P ∨ Q) logically entail ¬P ∨ ¬Q ? How could I find out?
Let’s have some notation to celebrate.

¬(P ∨ Q) ¬P ∨ ¬Q

‘logically entails’ vs ‘logically valid argument’

What happens if you do a web search for the term ‘logical consequence’?
The first result is an encyclopedia article. That seems promising ...
... except that it isn’t.
Wikipedia says that ‘A valid logical argument is one in which the conclusions follow from its premises’? And that is not at all how we are thinking about logical validity on this course.

help!?

Why does Wikipedia say that ‘A valid logical argument is one in which the conclusions follow from its premises’? Let me put it like this.
On this course our aim is to get a handle on formal logic. To this end we start with some stipulations about logical validity and related notions that almost everyone agrees are roughly right and acceptable simplifications.
These stipulations enable us to get a handle on formal logic while avoiding some interesting philosophical controversies about what logic is. This makes sense: you can’t really do philosophy of logic without any sense of what logic is.
But once you’ve understood something about formal logic, you can go on to think more critically about logical validity.
Logic is the study of logical validity, and what we are learning is logic. If you end up in a position to criticise our defintions of logical validity, it will be on the basis of your understanding of what logic is.

What does ‘logically entail’ mean?

One sentence logically entails another just if there’s no possible situation where the first is true and the second false.

 

Subproofs Are Tricky: The Answer

 
\section{Subproofs Are Tricky: The Answer}
 
\section{Subproofs Are Tricky: The Answer}
 

¬Intro Proof Example

 
\section{¬Intro Proof Example}
\emph{Reading:} §5.3, §6.3
 
\section{¬Intro Proof Example}
6.24--6.26
 

DeMorgan: ¬(A ∧ B) ⫤⊨ ¬A ∨ ¬B

 
\section{DeMorgan: ¬(A ∧ B) ⫤⊨ ¬A ∨ ¬B}
\emph{Reading:} §3.6, §4.2
 
\section{DeMorgan: ¬(A ∧ B) ⫤⊨ ¬A ∨ ¬B}
`$\leftmodels\models$' means `is logically equivalent to', so for now `has the same truth table as'.
A $\leftmodels\models$ ¬¬A
¬(A ∧ B) $\leftmodels\models$ (¬A ∨ ¬B)
¬(A ∨ B) $\leftmodels\models$ (¬A ∧ ¬B)
A → B $\leftmodels\models$ ¬A ∨ B
¬(A → B) $\leftmodels\models$ ¬(¬A ∨ B) $\leftmodels\models$ A ∧ ¬B
Here's a useful equivalence: double negations cancel out (at least in logic).

A ⫤⊨ ¬¬A

is logically equivalent to

i.e. has the same truth table as

A¬A¬¬A
TFT
FTF
¬(A ∧ B)    ⫤⊨     (¬A ∨ ¬B)
¬(A ∨ B)⫤⊨(¬A ∧ ¬B)
A → B⫤⊨¬A ∨ B
¬(A → B)⫤⊨¬(¬A ∨ B)    ⫤⊨    A ∧ ¬B
ABA ∧ B¬(A ∧ B)¬A¬B¬A ∨ ¬B
TTTFFFF
TFFTFTT
FTFTTFT
FFFTTTT
AB¬(A ∨ B)¬A ∧ ¬B
TTFF
TFFF
FTFF
FFTT
ABA → B¬A ∨ B
TTTT
TFFF
FTTT
FFTT
ABA → B¬(A → B)¬(¬A ∨ B)A ∧ ¬B
TTTFFF
TFFTTT
FTTFFF
FFTFFF
3.19
4.15--18
7.1--7.2, *7.3--7.6
3.19
4.31
 

Everything Is Broken

 
\section{Get Some Quantifiers: Don't Economise}
 
\section{Everything Is Broken}
\emph{Reading:} §9.1, §9.2
 
\section{Everything Is Broken}
Everything is broken: ∀x Broken(x)
Something is broken: ∃x Broken(x)
9.1 odd numbers only
9.2 even numbers only
9.8–-9.10