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\def \ititle {Logic I}
\def \isubtitle {Lecture 12}
\begin{center}
{\Large
\textbf{\ititle}: \isubtitle
}
\iemail %
\end{center}
Readings refer to sections of the course textbook, \emph{Language, Proof and Logic}.
9.20
13.1--13.4, 13.10--13.15, *13.16
\section{Relations: Reflexive, Symmetric}
\emph{Reading:} §15.1, §15.6
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A \emph{reflexive} relation is one that everything bears to itself. (E.g. everything is the SameShape as itself. E.g. of non-reflexive: not everything is LeftOf itself).
A \emph{symmetric} relation is one such that if x bears it to y, then y bears it to x. (E.g. Adjacent(x,y) is symmetric, LeftOf(x,y) is not symmetric.)
\section{Relations: Transitivity}
\emph{Reading:} §15.1, §15.6
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A \emph{transitive} relation is one such that if x bears it to y and y bears it to z then x bears it to z. (E.g. LeftOf is transitive; NotAdjacent is not transitive.)
\begin{minipage}{\columnwidth}
If NotAdjacent were transitive, the following argument would be logically valid:
\end{minipage}
\begin{minipage}{\columnwidth}
A counterexample to this argument:
\end{minipage}
express the counterexample formally
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Domain
{0, 1, 2}
Names
a : 0
b : 1
c : 2
Predicates
NotAdjacent : {
<0,1>, <1,2>,
<1,0>, <2,1>
}
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Domain
{0, 1, 2}
Names
a : 0
b : 1
c : 2
Predicates
NotAdjacent : {
<0,1>, <1,2>,
<1,0>, <2,1>
}
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Domain
{0, 1, 2}
Names
a : 0
b : 1
c : 2
Predicates
NotAdjacent : {
<0,1>, <1,2>,
<1,0>, <2,1>
}
\section{Relations: Some Examples}
\emph{Reading:} §15.1, §15.6
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Artificial relations ...
EqualToOrLeftOf(x, y) iff
\hspace{3mm} x = y or LeftOf(x, y)
EqualToOrAdjacent(x, y) iff
\hspace{3mm} x=y or Adjacent(x, y)
JohnOrAyesha(x, y) iff
\hspace{3mm} x = John and y = Ayesha
\hspace{3mm} or x = Ayesha and y = John
JohnToAyesha(x, y) iff
\hspace{3mm} x = John and y = Ayesha
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Defining Relations Using Dot-Arrow Diagrams
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Expressing Relations with Quantifiers
\section{Expressing Relations with Quantifiers}
\emph{Reading:} §15.1, §15.6
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\begin{minipage}{\columnwidth}
A \emph{reflexive} relation is one that everything bears to itself. (E.g. SameShape)
reflexive: ∀x R(x,x)
\end{minipage}
\begin{minipage}{\columnwidth}
A \emph{symmetric} relation is one such that if x bears it to y, then y bears it to x. (E.g. Adjacent(x,y))
symmetric: ∀x∀y ( R(x,y) → R(y,x) )
\end{minipage}
\begin{minipage}{\columnwidth}
A \emph{transitive} relation is one such that if x bears it to y and y bears it to z then x bears it to z. (E.g. LeftOf is transitive; DifferentShape is not transitive)
transitive: ∀x∀y∀z ( ( R(x,y) ∧ R(y,z) ) → R(x,z) )
\end{minipage}
15.33--15.40 (second edition)
15.33, 15.37--15.39 (second edition)
feedback
‘You could recommend an introduction to logic or an introduction to thinking about logic’
- Stephen Read,Thinking about Logic
- Mark Sainsbury,Logical Forms
\section{Negating Identity}
| } these mean the same thing |
Ayesha is not Beatrice.
It’s not true that: Ayesha is Beatrice
Ayesha is this: not Beatrice (?)
(¬a)=b
<== don’t do this either!
\section{There Does Not Exist}
Something is not dead:
\hspace{3mm} ∃x ¬Dead(x)
Nothing is dead:
\hspace{3mm} ¬∃x Dead(x)
Everything is not broken:
\hspace{3mm} ∀x ¬Broken(x)
Not everything is broken:
\hspace{3mm} ¬∀x Broken(x)
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Something is dead.
∃x Dead(x)
Something is not dead.
∃x ¬Dead(x)
Nothing is dead.
¬∃x Dead(x)
| 1. | | |
| 2. | a=a | =Intro |
| 3. | ∃x (x=x) | ∃Intro: 2 |
Everything is broken.
∀x Broken(x)
Everything is not broken.
∀x ¬Broken(x)
Not everything is broken.
¬∀x Broken(x)
| 1. | ¬∃x Dead(x) | |
| | 2. | Dead(a) | | | 3. | ∃x Dead(x) | ∃Intro: 2 | | 4. | ⊥ | ⊥Intro: 1,3 |
|
| 5. | ¬Dead(a) | ¬Intro: 2-4 |
| 6. | ∃x ¬Dead(x) | ∃Intro: 5 |
| 1. | ∃x ¬Dead(x) | |
| 2. | ¬∃x Dead(x) | |
Counterexample:
Domain: {Ayesha, Beatrice}
Dead : { <Beatrice> }
a : Ayesha ; b : Beatrice
... Dead(b) is true; so the conclusion, ¬∃x Dead(x), is false
... and ¬Dead(a) is true; so the premise, ∃x ¬Dead(x), is true
9.12
9.18--9.19
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Expressing Counterexamples Formally
\section{Expressing Counterexamples Formally}
\emph{Reading:} §15.1, §15.6
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Give a counterexample to this argument:
Informally:
Formally:
\hspace{3mm} Domain: \{a, b\}
\hspace{3mm} R: \{<a,a>, <a,b>, <b,b>\}
Here’s a quick look at how to enter the counterexample in
zoxiy. If you want more detail, please see the user guide
(which is linked to on the home page of zoxiy).
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Proof Example: A∧B therefore ¬(¬A∨¬B).
\section{Proof Example: A∧B therefore ¬(¬A∨¬B).}
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Proof Example: P therefore ¬¬P.
\section{Proof Example: P therefore ¬¬P.}
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Proof Example: S∨(Q∧R) therefore S∨Q.
\section{Proof Example: S∨(Q∧R) therefore S∨Q.}